Math Dump /sym/f3c981
id=246752 · host=fr.findroms.cloud · 2026-08-20 02:11Z
∑_{k=1}^{n} k = n(n+1)/2
det| 10 9 ; 1 11 | = 101
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
∫₀^∞ e^(-ω²) dω = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
79K
7α² + 7α + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
43K
det| 3 9 ; 7 4 | = -51
3φ² + 6φ + 0 = 0
det| 12 3 ; 5 13 | = 141
4ψ² + 4ψ + 2 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∇²t = 0