Math Dump /sym/b8dd66
id=363088 · host=fr.findroms.cloud · 2026-08-20 02:17Z
e^{i\pi} + 1 = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
6β² + 5β + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
79K
∇²x = 0
∑_{k=1}^{n} k = n(n+1)/2
43K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
E = mc²
λ = h/p
ω = 2πf
\frac{3}{1} \sum_{i=1}^{n} i^{2}
det| 5 4 ; 1 6 | = 26