Math Dump /sym/c825ed
id=372189 · host=fr.findroms.cloud · 2026-08-20 02:12Z
∇ × E = −∂B/∂t
10t² + 4t + 6 = 0
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
79K
2r² + 2r + 3 = 0
∑_{k=1}^{n} k = n(n+1)/2
43K
1x² + 3x + 5 = 0
\lim_{n\to 0} \frac{\sin n}{n} = 1
3z² + 1z + 5 = 0
\lim_{β\to 0} \frac{\sin β}{β} = 1
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O