Math Dump /sym/19d5bf
id=437511 · host=fr.findroms.cloud · 2026-08-20 02:16Z
4y² + 5y + 4 = 0
∫₀^∞ e^(-n²) dn = √π / 2
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
11y² + 2y + 0 = 0
∑_{k=1}^{n} k = n(n+1)/2
79K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
43K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
d/dn [n^12] = 12n^11
∂ψ/∂θ = 5ψ
N₂ + 3H₂ ⇌ 2NH₃
7z² + 1z + 6 = 0
7θ² + 4θ + 4 = 0