Math Dump /sym/4b59c5
id=471851 · host=fr.findroms.cloud · 2026-08-20 02:20Z
12r² + 7r + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
7ψ² + 1ψ + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
79K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
43K
λ = h/p
∫₀^∞ e^(-ψ²) dψ = √π / 2
iħ ∂ψ/∂t = Ĥψ
E = mc²
5ψ² + 7ψ + 0 = 0
det| 11 2 ; 2 12 | = 128