Math Dump /sym/14ade4
id=494058 · host=fr.findroms.cloud · 2026-08-20 02:16Z
∇ × E = −∂B/∂t
9y² + 5y + 3 = 0
det| 5 6 ; 2 6 | = 18
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det| 3 7 ; 2 4 | = -2
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ω = 2πf
∑_{k=1}^{n} k = n(n+1)/2
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det| 9 4 ; 0 10 | = 90
∑_{k=1}^{n} k = n(n+1)/2
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8n² + 4n + 6 = 0
det| 5 6 ; 5 6 | = 0
F = ma
∇²ω = 0
8z² + 8z + 7 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}