Math Dump /sym/da2ee7
id=543818 · host=fr.findroms.cloud · 2026-09-12 10:17Z
5ω² + 3ω + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
det| 5 6 ; 2 6 | = 18
381K
det| 3 7 ; 2 4 | = -2
258K
8n² + 6n + 5 = 0
∑_{k=1}^{n} k = n(n+1)/2
349K
CaCO₃ → CaO + CO₂
∑_{k=1}^{n} k = n(n+1)/2
469K
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
det| 2 5 ; 0 3 | = 6
1θ² + 1θ + 2 = 0
∫₀^∞ e^(-y²) dy = √π / 2
∑_{k=1}^{n} k = n(n+1)/2