Math Dump /sym/a47911
id=551855 · host=fr.findroms.cloud · 2026-08-20 02:17Z
e^{i\pi} + 1 = 0
∇ × E = −∂B/∂t
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
det| 8 9 ; 2 9 | = 54
∑_{k=1}^{n} k = n(n+1)/2
79K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
43K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
ω = 2πf
ΔS ≥ 0
1ψ² + 8ψ + 0 = 0
12z² + 2z + 6 = 0