Math Dump /sym/8b9592
id=667314 · host=fr.findroms.cloud · 2026-08-20 02:17Z
det| 4 8 ; 2 5 | = 4
N₂ + 3H₂ ⇌ 2NH₃
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
det| 2 6 ; 0 3 | = 6
∑_{k=1}^{n} k = n(n+1)/2
79K
∫₀^∞ e^(-α²) dα = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
43K
2H₂ + O₂ → 2H₂O
ω = 2πf
det| 4 6 ; 7 5 | = -22
\frac{4}{6} \sum_{i=1}^{n} i^{2}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
d/dz [z^10] = 10z^9