Math Dump /sym/da1975
id=688651 · host=fr.findroms.cloud · 2026-08-20 02:15Z
F = ma
det| 4 9 ; 1 5 | = 11
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
N₂ + 3H₂ ⇌ 2NH₃
∑_{k=1}^{n} k = n(n+1)/2
79K
11ψ² + 1ψ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
43K
8φ² + 8φ + 4 = 0
det| 4 1 ; 2 5 | = 18
det| 8 6 ; 5 9 | = 42
9φ² + 8φ + 4 = 0
ω = 2πf
ΔS ≥ 0