Math Dump /sym/804ae2
id=727995 · host=fr.findroms.cloud · 2026-08-20 02:12Z
∇ × E = −∂B/∂t
11θ² + 6θ + 1 = 0
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
79K
det| 3 1 ; 7 4 | = 5
∑_{k=1}^{n} k = n(n+1)/2
43K
10r² + 5r + 3 = 0
11β² + 8β + 6 = 0
ΔS ≥ 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
\lim_{z\to 0} \frac{\sin z}{z} = 1
det| 5 1 ; 3 6 | = 27