Math Dump /sym/781a6f
id=729341 · host=fr.findroms.cloud · 2026-08-26 14:49Z
∑_{k=1}^{n} k = n(n+1)/2
1θ² + 6θ + 3 = 0
det| 5 6 ; 2 6 | = 18
28K
det| 3 7 ; 2 4 | = -2
157K
∇²r = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
det| 8 9 ; 7 9 | = 9
∑_{k=1}^{n} k = n(n+1)/2
275K
det| 12 4 ; 2 13 | = 148
e^{i\pi} + 1 = 0
e^{i\pi} + 1 = 0
3θ² + 4θ + 0 = 0
∇²φ = 0
AgNO₃ + NaCl → AgCl↓ + NaNO₃