Math Dump /sym/0ad064
id=744235 · host=fr.findroms.cloud · 2026-08-26 14:51Z
2θ² + 2θ + 4 = 0
iħ ∂ψ/∂t = Ĥψ
det| 5 6 ; 2 6 | = 18
28K
det| 3 7 ; 2 4 | = -2
157K
7t² + 5t + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
276K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
275K
Fe₂O₃ + 3CO → 2Fe + 3CO₂
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∇²θ = 0
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
8α² + 7α + 4 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}