Math Dump /sym/5da705
id=805232 · host=fr.findroms.cloud · 2026-08-20 02:11Z
det| 5 5 ; 6 6 | = 0
N₂ + 3H₂ ⇌ 2NH₃
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
det| 1 6 ; 6 2 | = -34
∑_{k=1}^{n} k = n(n+1)/2
79K
∇²r = 0
∑_{k=1}^{n} k = n(n+1)/2
43K
∇ × E = −∂B/∂t
N₂ + 3H₂ ⇌ 2NH₃
\frac{2}{1} \sum_{i=1}^{n} i^{2}
7γ² + 6γ + 3 = 0
N₂ + 3H₂ ⇌ 2NH₃
d/dn [n^12] = 12n^11