Math Dump /sym/5b24c6
id=842605 · host=fr.findroms.cloud · 2026-08-20 02:20Z
det| 1 4 ; 7 2 | = -26
ω = 2πf
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
12θ² + 9θ + 1 = 0
∑_{k=1}^{n} k = n(n+1)/2
79K
CH₄ + 2O₂ → CO₂ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
43K
∑_{k=1}^{n} k = n(n+1)/2
∑_{k=1}^{n} k = n(n+1)/2
d/dt [t^12] = 12t^11
ΔS ≥ 0
3ω² + 2ω + 3 = 0
5z² + 7z + 5 = 0