Math Dump /sym/cecb52
id=845288 · host=fr.findroms.cloud · 2026-08-20 02:14Z
det| 6 3 ; 2 7 | = 36
∑_{k=1}^{n} k = n(n+1)/2
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
6φ² + 1φ + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
79K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
43K
∂r/∂ψ = 3r
Fe₂O₃ + 3CO → 2Fe + 3CO₂
d/dx [x^4] = 4x^3
F = ma
det| 6 7 ; 5 7 | = 7
det| 3 1 ; 2 4 | = 10