Math Dump /sym/f3aa91
id=872982 · host=fr.findroms.cloud · 2026-09-12 10:17Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
det| 5 6 ; 2 6 | = 18
381K
det| 3 7 ; 2 4 | = -2
258K
det| 3 4 ; 1 4 | = 8
∑_{k=1}^{n} k = n(n+1)/2
349K
∇ × E = −∂B/∂t
∑_{k=1}^{n} k = n(n+1)/2
469K
∑_{k=1}^{n} k = n(n+1)/2
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
∑_{k=1}^{n} k = n(n+1)/2
PV = nRT
2n² + 5n + 1 = 0
\binom{n}{k} = \frac{n!}{k!(n-k)!}