Math Dump /sym/4e1188
id=879966 · host=fr.findroms.cloud · 2026-08-20 02:15Z
\binom{n}{k} = \frac{n!}{k!(n-k)!}
F = ma
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
det| 1 5 ; 0 2 | = 2
∑_{k=1}^{n} k = n(n+1)/2
79K
PV = nRT
∑_{k=1}^{n} k = n(n+1)/2
43K
∇ × E = −∂B/∂t
CaCO₃ → CaO + CO₂
\binom{n}{k} = \frac{n!}{k!(n-k)!}
3α² + 2α + 4 = 0
∑_{k=1}^{n} k = n(n+1)/2
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂