Math Dump /sym/536ca4
id=900955 · host=fr.findroms.cloud · 2026-08-20 02:18Z
∇²n = 0
2ψ² + 2ψ + 4 = 0
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
∂ω/∂θ = 5ω
∑_{k=1}^{n} k = n(n+1)/2
79K
det| 11 9 ; 7 12 | = 69
∑_{k=1}^{n} k = n(n+1)/2
43K
10z² + 1z + 4 = 0
e^{i\pi} + 1 = 0
ΔS ≥ 0
∑_{k=1}^{n} k = n(n+1)/2
\frac{11}{8} \sum_{i=1}^{n} i^{2}
2t² + 6t + 5 = 0