Math Dump /sym/f5fc44
id=930655 · host=fr.findroms.cloud · 2026-08-20 02:14Z
\frac{11}{4} \sum_{i=1}^{n} i^{2}
∑_{k=1}^{n} k = n(n+1)/2
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
det| 7 5 ; 3 8 | = 41
∑_{k=1}^{n} k = n(n+1)/2
79K
AgNO₃ + NaCl → AgCl↓ + NaNO₃
∑_{k=1}^{n} k = n(n+1)/2
43K
PV = nRT
∑_{k=1}^{n} k = n(n+1)/2
ω = 2πf
F = ma
det| 5 9 ; 5 6 | = -15
det| 6 4 ; 6 7 | = 18