Math Dump /sym/153951
id=953069 · host=fr.findroms.cloud · 2026-09-12 10:16Z
∑_{k=1}^{n} k = n(n+1)/2
12ψ² + 1ψ + 6 = 0
det| 5 6 ; 2 6 | = 18
381K
det| 3 7 ; 2 4 | = -2
258K
d/dφ [φ^9] = 9φ^8
∑_{k=1}^{n} k = n(n+1)/2
349K
det| 4 1 ; 4 5 | = 16
∑_{k=1}^{n} k = n(n+1)/2
469K
7γ² + 9γ + 5 = 0
9φ² + 9φ + 3 = 0
F = ma
Fe₂O₃ + 3CO → 2Fe + 3CO₂
3n² + 8n + 1 = 0
\frac{2}{7} \sum_{i=1}^{n} i^{2}