Math Dump /sym/050d95
id=994519 · host=fr.findroms.cloud · 2026-08-20 02:18Z
∇ × E = −∂B/∂t
det| 5 5 ; 2 6 | = 20
det| 5 6 ; 2 6 | = 18
366K
det| 3 7 ; 2 4 | = -2
475K
∫₀^∞ e^(-n²) dn = √π / 2
∑_{k=1}^{n} k = n(n+1)/2
79K
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
43K
det| 6 1 ; 3 7 | = 39
\oint_C \vec{F}\cdot d\vec{r} = 0
∑_{k=1}^{n} k = n(n+1)/2
iħ ∂ψ/∂t = Ĥψ
det| 7 7 ; 5 8 | = 21
det| 5 7 ; 4 6 | = 2