Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-08-21 15:19Z
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
3φ² + 2φ + 1 = 0
det| 5 6 ; 2 6 | = 18
90K
det| 3 7 ; 2 4 | = -2
394K
C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂
∑_{k=1}^{n} k = n(n+1)/2
226K
3r² + 6r + 7 = 0
∑_{k=1}^{n} k = n(n+1)/2
60K
\lim_{r\to 0} \frac{\sin r}{r} = 1
7r² + 4r + 3 = 0
\lim_{β\to 0} \frac{\sin β}{β} = 1
det| 1 2 ; 0 2 | = 2
∇ × E = −∂B/∂t
F = ma