Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-17 22:39Z

N₂ + 3H₂ ⇌ 2NH₃

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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9ψ² + 4ψ + 2 = 0

\lim_{α\to 0} \frac{\sin α}{α} = 1

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iħ ∂ψ/∂t = Ĥψ

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d/dβ [β^6] = 6β^5

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 3 1 ; 7 4 | = 5

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det| 6 1 ; 4 7 | = 38

\lim_{t\to 0} \frac{\sin t}{t} = 1

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E = mc²

298K

d/dt [t^3] = 3t^2

447K

PV = nRT

297K

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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8ψ² + 7ψ + 0 = 0

412K