Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 00:44Z

d/dy [y^8] = 8y^7

E = mc²

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N₂ + 3H₂ ⇌ 2NH₃

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\lim_{x\to 0} \frac{\sin x}{x} = 1

∫₀^∞ e^(-α²) dα = √π / 2

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\lim_{α\to 0} \frac{\sin α}{α} = 1

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d/dn [n^3] = 3n^2

10ω² + 7ω + 4 = 0

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CH₄ + 2O₂ → CO₂ + 2H₂O

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6t² + 4t + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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det| 7 4 ; 4 8 | = 40

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