Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:38Z

det| 6 5 ; 4 7 | = 22

λ = h/p

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∑_{k=1}^{n} k = n(n+1)/2

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∇²φ = 0

10t² + 9t + 5 = 0

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∇ × E = −∂B/∂t

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\frac{9}{2} \sum_{i=1}^{n} i^{2}

CH₄ + 2O₂ → CO₂ + 2H₂O

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d/dt [t^3] = 3t^2

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∫₀^∞ e^(-θ²) dθ = √π / 2

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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8ψ² + 7ψ + 0 = 0

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E = mc²

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