Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:41Z

11n² + 5n + 4 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

460K

N₂ + 3H₂ ⇌ 2NH₃

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 5 3 ; 7 6 | = 9

186K

2n² + 4n + 0 = 0

411K

4φ² + 6φ + 2 = 0

det| 7 4 ; 4 8 | = 40

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

11t² + 9t + 7 = 0

459K

∑_{k=1}^{n} k = n(n+1)/2

406K

6x² + 6x + 1 = 0

181K

PV = nRT

80K