Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:36Z

det| 6 5 ; 4 7 | = 22

∇ × E = −∂B/∂t

460K

2H₂ + O₂ → 2H₂O

438K

∇²φ = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

186K

∫₀^∞ e^(-ω²) dω = √π / 2

411K

\frac{9}{2} \sum_{i=1}^{n} i^{2}

iħ ∂ψ/∂t = Ĥψ

448K

\lim_{t\to 0} \frac{\sin t}{t} = 1

22K

8ψ² + 7ψ + 0 = 0

459K

det| 5 2 ; 3 6 | = 24

406K

d/dt [t^3] = 3t^2

181K

det| 10 2 ; 3 11 | = 104

80K

E = mc²

359K

10t² + 9t + 5 = 0

455K