Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 15:14Z

2H₂ + O₂ → 2H₂O

∇²t = 0

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∑_{k=1}^{n} k = n(n+1)/2

264K

det| 8 7 ; 2 9 | = 58

\lim_{r\to 0} \frac{\sin r}{r} = 1

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det| 7 2 ; 7 8 | = 42

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d/dn [n^11] = 11n^10

8ψ² + 7ψ + 0 = 0

48K

iħ ∂ψ/∂t = Ĥψ

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

377K

∑_{k=1}^{n} k = n(n+1)/2

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∑_{k=1}^{n} k = n(n+1)/2

401K

∇ × E = −∂B/∂t

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d/dt [t^3] = 3t^2

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