Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:33Z

11n² + 5n + 4 = 0

10β² + 4β + 1 = 0

460K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

438K

∫₀^∞ e^(-x²) dx = √π / 2

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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PV = nRT

411K

4φ² + 6φ + 2 = 0

F = G m₁m₂ / r²

448K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∫₀^∞ e^(-φ²) dφ = √π / 2

∇ × E = −∂B/∂t

459K

e^{i\pi} + 1 = 0

406K

N₂ + 3H₂ ⇌ 2NH₃

181K

det| 7 8 ; 4 8 | = 24

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det| 7 4 ; 4 8 | = 40

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\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

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