Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 18:49Z

CaCO₃ → CaO + CO₂

d/dt [t^3] = 3t^2

460K

∑_{k=1}^{n} k = n(n+1)/2

438K

\frac{12}{2} \sum_{i=1}^{n} i^{2}

\lim_{ω\to 0} \frac{\sin ω}{ω} = 1

186K

6t² + 6t + 4 = 0

411K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

Fe₂O₃ + 3CO → 2Fe + 3CO₂

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CaCO₃ → CaO + CO₂

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det| 8 5 ; 7 9 | = 37

∂x/∂ψ = 6x

459K

iħ ∂ψ/∂t = Ĥψ

406K

det| 5 8 ; 0 6 | = 30

∇ × E = −∂B/∂t

181K

8ψ² + 7ψ + 0 = 0

80K

det| 12 1 ; 5 13 | = 151

359K