Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 20:37Z

det| 6 5 ; 4 7 | = 22

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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∇ × E = −∂B/∂t

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∇²φ = 0

det| 3 7 ; 2 4 | = -2

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iħ ∂ψ/∂t = Ĥψ

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\frac{9}{2} \sum_{i=1}^{n} i^{2}

N₂ + 3H₂ ⇌ 2NH₃

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F = ma

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F = ma

\lim_{t\to 0} \frac{\sin t}{t} = 1

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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d/dt [t^3] = 3t^2

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∑_{k=1}^{n} k = n(n+1)/2

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∇ × E = −∂B/∂t

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8ψ² + 7ψ + 0 = 0

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