Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:01Z

11t² + 8t + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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∂ω/∂β = 7ω

d/dt [t^3] = 3t^2

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 3 3 ; 7 4 | = -9

λ = h/p

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det| 9 4 ; 1 10 | = 86

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det| 10 2 ; 3 11 | = 104

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∑_{k=1}^{n} k = n(n+1)/2

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6n² + 7n + 6 = 0

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