Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:08Z

10y² + 2y + 6 = 0

6t² + 6t + 4 = 0

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∇²θ = 0

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∫₀^∞ e^(-t²) dt = √π / 2

∫₀^∞ e^(-ω²) dω = √π / 2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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e^{i\pi} + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

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d/dt [t^3] = 3t^2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

e^{i\pi} + 1 = 0

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1θ² + 2θ + 6 = 0

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λ = h/p

∂n/∂θ = 3n

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∇²β = 0

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det| 9 4 ; 1 10 | = 86

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