Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:59Z

11n² + 5n + 4 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

e^{i\pi} + 1 = 0

438K

∫₀^∞ e^(-x²) dx = √π / 2

2H₂ + O₂ → 2H₂O

186K

det| 7 2 ; 7 8 | = 42

411K

4φ² + 6φ + 2 = 0

8ψ² + 7ψ + 0 = 0

448K

6ω² + 4ω + 4 = 0

22K

λ = h/p

459K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

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det| 9 8 ; 3 10 | = 66

181K

N₂ + 3H₂ ⇌ 2NH₃

80K

iħ ∂ψ/∂t = Ĥψ

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