Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:23Z

∇²n = 0

∑_{k=1}^{n} k = n(n+1)/2

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det| 1 4 ; 3 2 | = -10

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9r² + 4r + 1 = 0

∑_{k=1}^{n} k = n(n+1)/2

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∫₀^∞ e^(-θ²) dθ = √π / 2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 9 4 ; 1 10 | = 86

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d/dt [t^3] = 3t^2

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2n² + 4n + 0 = 0

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∑_{k=1}^{n} k = n(n+1)/2

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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