Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 04:31Z

∇²n = 0

∫₀^∞ e^(-r²) dr = √π / 2

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iħ ∂ψ/∂t = Ĥψ

263K

9r² + 4r + 1 = 0

∇²t = 0

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PV = nRT

108K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

8ψ² + 7ψ + 0 = 0

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\binom{n}{k} = \frac{n!}{k!(n-k)!}

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11γ² + 3γ + 6 = 0

det| 3 1 ; 7 4 | = 5

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10ψ² + 5ψ + 0 = 0

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\lim_{ψ\to 0} \frac{\sin ψ}{ψ} = 1

4t² + 3t + 3 = 0

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∇ × E = −∂B/∂t

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det| 6 1 ; 3 7 | = 39

N₂ + 3H₂ ⇌ 2NH₃

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C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

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N₂ + 3H₂ ⇌ 2NH₃