Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:00Z

11n² + 5n + 4 = 0

E = mc²

460K

∇ × E = −∂B/∂t

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∫₀^∞ e^(-x²) dx = √π / 2

det| 1 4 ; 3 2 | = -10

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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4φ² + 6φ + 2 = 0

\frac{8}{7} \sum_{i=1}^{n} i^{2}

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∫₀^∞ e^(-θ²) dθ = √π / 2

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∫₀^∞ e^(-φ²) dφ = √π / 2

8ψ² + 7ψ + 0 = 0

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\lim_{t\to 0} \frac{\sin t}{t} = 1

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d/dt [t^3] = 3t^2

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