Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 23:11Z

11t² + 8t + 0 = 0

∑_{k=1}^{n} k = n(n+1)/2

460K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

438K

∂ω/∂β = 7ω

e^{i\pi} + 1 = 0

186K

∇²β = 0

411K

det| 3 3 ; 7 4 | = -9

iħ ∂ψ/∂t = Ĥψ

448K

∑_{k=1}^{n} k = n(n+1)/2

22K

PV = nRT

\lim_{r\to 0} \frac{\sin r}{r} = 1

459K

PV = nRT

406K

Fe₂O₃ + 3CO → 2Fe + 3CO₂

d/dt [t^3] = 3t^2

181K

det| 5 9 ; 7 6 | = -33

80K

det| 9 4 ; 1 10 | = 86

359K

7γ² + 8γ + 3 = 0

455K