Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:41Z

11n² + 5n + 4 = 0

d/dφ [φ^1] = 1φ^0

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

e^{i\pi} + 1 = 0

186K

PV = nRT

411K

4φ² + 6φ + 2 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

448K

F = G m₁m₂ / r²

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

459K

det| 7 2 ; 7 8 | = 42

406K

∇²ω = 0

iħ ∂ψ/∂t = Ĥψ

181K

8x² + 2x + 7 = 0

80K

det| 9 4 ; 1 10 | = 86

359K

1θ² + 2θ + 6 = 0

455K