Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:38Z

10y² + 2y + 6 = 0

∇ × E = −∂B/∂t

460K

\oint_C \vec{F}\cdot d\vec{r} = 0

438K

∫₀^∞ e^(-t²) dt = √π / 2

∇²t = 0

186K

∑_{k=1}^{n} k = n(n+1)/2

411K

e^{i\pi} + 1 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

448K

8ψ² + 7ψ + 0 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

d/dt [t^3] = 3t^2

459K

ω = 2πf

406K

λ = h/p

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

359K

1n² + 7n + 3 = 0

455K