Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:57Z

11n² + 5n + 4 = 0

8ψ² + 7ψ + 0 = 0

460K

iħ ∂ψ/∂t = Ĥψ

438K

∫₀^∞ e^(-x²) dx = √π / 2

e^{i\pi} + 1 = 0

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N₂ + 3H₂ ⇌ 2NH₃

411K

4φ² + 6φ + 2 = 0

\lim_{β\to 0} \frac{\sin β}{β} = 1

448K

\lim_{α\to 0} \frac{\sin α}{α} = 1

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∫₀^∞ e^(-φ²) dφ = √π / 2

det| 10 7 ; 3 11 | = 89

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ω = 2πf

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ΔS ≥ 0

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e^{i\pi} + 1 = 0

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H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

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