Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:17Z

11n² + 5n + 4 = 0

∇ × E = −∂B/∂t

460K

\lim_{β\to 0} \frac{\sin β}{β} = 1

438K

∫₀^∞ e^(-x²) dx = √π / 2

det| 2 6 ; 0 3 | = 6

186K

12γ² + 9γ + 1 = 0

411K

4φ² + 6φ + 2 = 0

∑_{k=1}^{n} k = n(n+1)/2

448K

F = G m₁m₂ / r²

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

det| 7 4 ; 4 8 | = 40

459K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

406K

∇²ω = 0

10γ² + 8γ + 7 = 0

181K

∑_{k=1}^{n} k = n(n+1)/2

80K

\lim_{r\to 0} \frac{\sin r}{r} = 1

359K

F = G m₁m₂ / r²

455K