Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-20 06:35Z

∑_{k=1}^{n} k = n(n+1)/2

11z² + 3z + 4 = 0

273K

det| 9 8 ; 3 10 | = 66

263K

e^{i\pi} + 1 = 0

6n² + 7n + 6 = 0

139K

12y² + 5y + 7 = 0

108K

2H₂ + O₂ → 2H₂O

iħ ∂ψ/∂t = Ĥψ

333K

det| 11 4 ; 5 12 | = 112

160K

8ψ² + 7ψ + 0 = 0

439K

∑_{k=1}^{n} k = n(n+1)/2

413K

∑_{k=1}^{n} k = n(n+1)/2

297K

N₂ + 3H₂ ⇌ 2NH₃

128K

\frac{2}{2} \sum_{i=1}^{n} i^{2}

404K