Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 15:25Z

11n² + 5n + 4 = 0

e^{i\pi} + 1 = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-x²) dx = √π / 2

d/dx [x^3] = 3x^2

186K

d/dt [t^3] = 3t^2

411K

4φ² + 6φ + 2 = 0

\binom{n}{k} = \frac{n!}{k!(n-k)!}

448K

∇²r = 0

22K

∫₀^∞ e^(-φ²) dφ = √π / 2

C₆H₁₂O₆ → 2C₂H₅OH + 2CO₂

459K

det| 1 4 ; 3 2 | = -10

406K

det| 9 4 ; 1 10 | = 86

181K

∇ × E = −∂B/∂t

80K

∑_{k=1}^{n} k = n(n+1)/2

359K