Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 21:03Z

10y² + 2y + 6 = 0

e^{i\pi} + 1 = 0

460K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

438K

∫₀^∞ e^(-t²) dt = √π / 2

det| 3 7 ; 2 4 | = -2

186K

d/dt [t^3] = 3t^2

411K

e^{i\pi} + 1 = 0

\frac{4}{6} \sum_{i=1}^{n} i^{2}

448K

11t² + 9t + 5 = 0

22K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

det| 5 3 ; 7 6 | = 9

459K

iħ ∂ψ/∂t = Ĥψ

406K

det| 9 4 ; 1 10 | = 86

181K

e^{i\pi} + 1 = 0

80K

∑_{k=1}^{n} k = n(n+1)/2

359K