Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-18 12:41Z
∑_{k=1}^{n} k = n(n+1)/2
det| 3 7 ; 2 4 | = -2
460K
4y² + 7y + 7 = 0
CH₄ + 2O₂ → CO₂ + 2H₂O
411K
∇²t = 0
det| 9 4 ; 1 10 | = 86
448K
6β² + 2β + 2 = 0
∑_{k=1}^{n} k = n(n+1)/2
406K