Math Dump /sym/6c3138
id=1 · host=fr.findroms.cloud · 2026-10-20 04:25Z
∇²n = 0
∑_{k=1}^{n} k = n(n+1)/2
273K
9r² + 4r + 1 = 0
∫₀^∞ e^(-α²) dα = √π / 2
139K
H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O
11γ² + 3γ + 6 = 0
∑_{k=1}^{n} k = n(n+1)/2
439K
det| 8 9 ; 4 9 | = 36
404K