Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-19 02:20Z

Fe₂O₃ + 3CO → 2Fe + 3CO₂

4t² + 3t + 3 = 0

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\frac{12}{6} \sum_{i=1}^{n} i^{2}

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\frac{8}{4} \sum_{i=1}^{n} i^{2}

d/dt [t^3] = 3t^2

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12γ² + 9γ + 1 = 0

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N₂ + 3H₂ ⇌ 2NH₃

10ψ² + 5ψ + 0 = 0

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Fe₂O₃ + 3CO → 2Fe + 3CO₂

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det| 5 9 ; 7 6 | = -33

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∇ × E = −∂B/∂t

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iħ ∂ψ/∂t = Ĥψ

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∫₀^∞ e^(-t²) dt = √π / 2

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8ψ² + 7ψ + 0 = 0

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∇²γ = 0

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