Math Dump /sym/6c3138

id=1 · host=fr.findroms.cloud · 2026-10-18 16:25Z

10γ² + 4γ + 3 = 0

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

460K

∫₀^∞ e^(-z²) dz = √π / 2

438K

d/dβ [β^11] = 11β^10

d/dt [t^3] = 3t^2

186K

8ψ² + 7ψ + 0 = 0

411K

3x² + 4x + 6 = 0

1n² + 7n + 3 = 0

448K

det| 2 3 ; 5 3 | = -9

22K

CaCO₃ → CaO + CO₂

\lim_{r\to 0} \frac{\sin r}{r} = 1

459K

∇ × E = −∂B/∂t

406K

H₂SO₄ + 2NaOH → Na₂SO₄ + 2H₂O

181K

d/dφ [φ^1] = 1φ^0

80K

det| 3 7 ; 2 4 | = -2

359K

\binom{n}{k} = \frac{n!}{k!(n-k)!}

455K